Answer
See the answer below.
Work Step by Step
a) From the table, doubling the concentration of CO, at the same O2 concentration, leads to the reaction rate being doubled, so the reaction is of order 1 in CO. Doubling the concentration of NO2, at the same CO concentration, leads to the reaction rate being doubled, so the reaction is of order 1 in NO2.
$r=k[CO][NO_2]$
b) From the first line of the table:
$3.4\times10^{-8}\ mol/L.h=k(0.00050\ mol/L)(0.00036\ mol/L)$
$k=1.89\ L/mol.h$
c) $r=1.89\times(0.0015)^2(0.00072)=2.04\times10^{-7}\ mol/L.s$
