Answer
$k=0.051\ L/mol.s$
Work Step by Step
For a second-order process:
$1/C-1/C_0=k.t$
$1/(0.79\times0.0087\ mol/L)-1/0.0087\ mol/L=k.600\ s$
$k=0.051\ L/mol.s$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553b: 22
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