Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505d: 74

Answer

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Work Step by Step

In 1 kg of water: Number of moles: $1000\ g\div 18.015\ g/mol=55.51\ mol$ Volume: $1000\ g\div 0.997\ g/cm^3=1003.0\ cm^3=1.003\ L$ Molality: $55.51\ mol\div 1\ kg=55.51\ m$ Molarity: $55.51\ mol\div 1.003\ L=55.34\ M$
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