Answer
See the answer below.
Work Step by Step
In 1 kg of the solution:
Mass of acetic acid: $5/100\times 1000\ g=50\ g$
Mass of water: $950\ g$
The number of moles of acetic acid: $50\ g/60.05\ g/mol=0.833\ mol$
The number of moles of water: $950\ g\div 18.015\ g/mol=52.74\ mol$
Mole fraction: $0.833/(0.833+52.74)=0.016$
Molality: $0.833\ mol/0.95\ kg=0.877\ mol/kg$
ppm concentration: $5/100\times 10^6=50\ 000\ ppm$
The molarity can't be calculated because, from the information provided, it's not possible to calculate the volume of the 1 kg calculation basis, for that, the density of the solution would be required.
