Answer
See the answer below.
Work Step by Step
By definition: $\Delta H^0_{soln}=\Delta H^0_f(aq)- \Delta H^0_f(s)$
Li2SO4: $\Delta H^0_{soln}=-1464.4-(-1436.4)=-28\ kJ/mol$ -> exothermic
K2SO4: $\Delta H^0_{soln}=-1413.0-(-1437.7)=+24.7\ kJ/mol$ -> endothermic
From table 13.1:
LiCl: $\Delta H^0_{soln}=-445.6-(-408.7)=-36.9\ kJ/mol$-> exothermic
KCl: $\Delta H^0_{soln}=-419.5-(-436.7)=+17.2\ kJ/mol$ -> endothermic
Both lithium salts have exothermic solubilization, while both potassium salts have endothermic ones.
