Answer
See the answer below.
Work Step by Step
Number of moles of iron:
$2.2\ g/div 55.845\ g/mol=0.0394\ mol$
From stoichiometry: $0.0394\ mol$ of $H_2$
From ideal gas law:
$P.V=n.R.T$
$P=0.082057\ L.atm/mol.K×0.0394\ mol×(25+273)\ K/10.0\ L$
$P=0.096\ atm$
