Answer
D
Work Step by Step
From the ideal gas law:
$m/V=PM/RT$
$M=0.082057\ L.atm/mol.K×(25+273)\ K/(24.8\ mmHg×1\ atm/760\ mmHg)×0.0125\ g/0.125\ L $
$M=74.94\ g/mol$
Atomic weights: B: 10.81 g/mol, H: 1.008 g/mol
Closest option: $B_6H_{10}$
$6×10.81+10×1.008=74.94\ g/mol$