Answer
See the answer below.
Work Step by Step
From the ideal gas law:
$P.V=n.R.T$
$n=30.0×10^3\ g\div 4.00\ g/mol=7500\ mol$
$V=7500\ mol×0.082057\ L.atm/mol.K×(22+273)\ K/1.20\ atm$
$V=151300\ L$
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