Answer
See the answer below.
Work Step by Step
From the ideal gas law:
$P.V=n.R.T$
$n=2.2\ g\div 44.0\ g/mol=0.05\ mol$
$V=0.05\ mol×0.082057\ L.atm/mol.K×(22+273)\ K/(318\ mmHg×1\ atm/760\ mmHg)$
$V=2.92\ L$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 10 Gases and Their Properties - Study Questions - Page 403b: 19
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