Answer
$\frac{1}{4}~cos~94.2^{\circ}$
Work Step by Step
We can use this identity: $cos~2x = 1-2~sin^2~x$
$\frac{1}{4}-\frac{1}{2}sin^2~47.1^{\circ}$
$= \frac{1}{4}~(1-2~sin^2~47.1^{\circ})$
$= \frac{1}{4}~cos~94.2^{\circ}$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 5 - Trigonometric Identities - Section 5.5 Double-Angle Identities - 5.5 Exercises - Page 237: 45
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