Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 248: 23

Answer

$$\sin75^\circ=\sin15^\circ\cos60^\circ+\cos15^\circ\sin60^\circ$$ 23 is with J.

Work Step by Step

$$\sin75^\circ$$ It is true that $$\sin75^\circ=\sin(15^\circ+60^\circ)$$ This fact points to the use of the sum identity for sine, stating that $$\sin(A+B)=\sin A\cos B+\cos A\sin B$$ Therefore, for $A=15^\circ$ and $B=60^\circ$: $$\sin75^\circ=\sin15^\circ\cos60^\circ+\cos15^\circ\sin60^\circ$$ The equation indicates that 23 should be matched with J.
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