Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 592: 60

Answer

$(3\sqrt 2,-\frac{\pi}{4})$.

Work Step by Step

To convert $(-3,3)$ into polar coordinates, we have $r=\sqrt {(-3)^2+(3)^2}=3\sqrt 2$ and $\theta=tan^{-1}(\frac{3}{-3})=-\frac{\pi}{4}$. Thus we have $(3\sqrt 2,-\frac{\pi}{4})$.
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