Answer
$(3\sqrt 2,-\frac{\pi}{4})$.
Work Step by Step
To convert $(-3,3)$ into polar coordinates, we have $r=\sqrt {(-3)^2+(3)^2}=3\sqrt 2$ and $\theta=tan^{-1}(\frac{3}{-3})=-\frac{\pi}{4}$. Thus we have $(3\sqrt 2,-\frac{\pi}{4})$.
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