Answer
$(0,3)$
Work Step by Step
The point $(x,y)$ in the rectangular coordinate system can be expressed as:
$x=r \ \cos(\theta)$, $y=r \ \sin(\theta) ...(1)$
Here, we have $r=-3$ and $ \theta= -90^{\circ}$
Plug these values in equation (1) to obtain:
$x=(-3) \cos(-90^{\circ})=(-3)(0)=0 \\
y=(-3) \sin(-90^{\circ})=(-3)(-1)=3$
Therefore, the point has coordinates $(0,3 )$ in the rectangular coordinate system.
