Answer
Amplitude= $3$
Period= $\dfrac{2\pi}{3}$
Work Step by Step
Recall:
For $y=A\cos{(ωx)}$, we have:
$\text{Amplitude}=|A|\quad \quad \text{and} \quad \quad \text{Period}=T=\frac{2\pi}{ω}$
In $y=-3\cos (3x)$ we have $A=-3$ and $\omega=3$, so
Amplitude =$|A|=|-3|=3$
Period $T=\dfrac{2\pi}{\omega}=\dfrac{2\pi}{3}$