Answer
$\text{Amplitude} = 2$
$\text{Period}=T= 2\pi$
Work Step by Step
Recall:
For $y=A\sin{({\omega}x)}$, we have:
$\text{Amplitude}=|A|$ and $\text{Period}=T=\frac{2\pi}{\omega}$
In $y=2\sin x$ we have $A=2$ and $\omega=1$, so
Amplitude= $|A|=2$
Period $T=\frac{2\pi}{\omega}=\frac{2\pi}{1}=2\pi$
