Answer
$\text{Amplitude}= 6$
$\text{Period}= 2$
Work Step by Step
Recall:
For $y=A\sin{(ωx)}$, we have:
$\text{Amplitude}=|A|\quad \quad \text{and} \quad \quad \text{Period}=T=\frac{2\pi}{ω}$
In $y=6\sin(\pi x)$ we have $A=6$ and $\omega=\pi$.
Amplitude= $|A|=|6|=6$
Period $T=\dfrac{2\pi}{\omega}=\dfrac{2\pi}{\pi}=2$