Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 459: 51

Answer

$114.59 \dfrac{rev}{hour}$

Work Step by Step

The circumference is given by: $C=2 \pi r$ where $ r$ is the radius. We know that the radius is half of the diameter (D). Here $C=(2 ) (\pi)(\dfrac{1}{4})=\dfrac{\pi}{2}$ Thus, the angular speed $ \nu$ can be computed as: $\dfrac{\nu}{C}=\dfrac {180 \ mph}{(\dfrac{\pi}{2}) \ \dfrac{miles}{rev}} \approx 114.59 \dfrac{rev}{hour}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.