Answer
$sin(t)= \frac{5\sqrt {29}}{29}$,
$cos(t)= -\frac{2\sqrt {29}}{29}$,
$tan(t)= -\frac{5}{2}$.
Work Step by Step
Given $x=-2, y=5$, we have $r=\sqrt {(-2)^2+5^2}=\sqrt {29}$ and:
$sin(t)=\frac{y}{r}=\frac{5\sqrt {29}}{29}$,
$cos(t)=\frac{x}{r}=-\frac{2\sqrt {29}}{29}$,
$tan(t)=\frac{y}{x}=-\frac{5}{2}$.
