Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 459: 45

Answer

$sin(t)= \frac{2\sqrt 2}{3}$, $cos(t)= -\frac{1}{3}$, $tan(t)= -2\sqrt 2$, $cot(t)= -\frac{\sqrt 2}{4}$, $sec(t)= -3$, $csc(t)= \frac{3\sqrt 2}{4}$.

Work Step by Step

Given $x=-\frac{1}{3}, y=\frac{2\sqrt 2}{3}, r=1$, we have: $sin(t)=y=\frac{2\sqrt 2}{3}$, $cos(t)=x=-\frac{1}{3}$, $tan(t)=\frac{y}{x}=-2\sqrt 2$, $cot(t)=\frac{1}{tan(t)}=-\frac{\sqrt 2}{4}$, $sec(t)=\frac{1}{cos(t)}=-3$, $csc(t)=\frac{1}{sin(t)}=\frac{3\sqrt 2}{4}$.
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