Answer
$s_1=8\pi \ in. $ and $s_2=\dfrac{16\pi}{3} \ in.$
Work Step by Step
The arc length (s) is given by: $s=R \cdot \theta$
We see that in thirty minutes, the tip of the minute hand rotates by an angle of $\pi$. This means that the tip has traveled a distance of $s_1=8 \cdot \pi=8 \pi$ inches.
Whereas, in twenty minutes, the tip of the minute hand rotates by an angle of $\dfrac{2\pi}{3}$. This means that the tip has traveled by a distance of $s_21=8 \cdot (2 \pi/3)=\dfrac{16 \pi}{3}$ inches.
Thus, $s_1=8\pi \ in. $ and $s_2=\dfrac{16\pi}{3} \ in.$
