Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.6 Logarithmic and Exponential Equations - 4.6 Assess Your Understanding - Page 337: 38

Answer

$1+\sqrt[3] 2 $

Work Step by Step

1. $log(x-1)=\frac{1}{3}log2 \Longrightarrow log(x-1)=log2^{\frac{1}{3}} \Longrightarrow x-1=2^{\frac{1}{3}} x=1+\sqrt[3] 2 $. 2. Check $x=1+\sqrt[3] 2 $ fit(s).
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