Answer
$x=-1,2$.
Work Step by Step
Step 1. For $x^4-x^3+2x^2-4x-8=0$, list possible rational real zeros $\frac{p}{q}: \pm1,\pm2,\pm4,\pm8$
Step 2. Use synthetic division as shown in the figure to find zero(s) $x=-1,2$.
Step 3. Use the quotient to find other zeros: $x^2+4=0$ no real solutions.