Answer
Remainder = $0$
$(x-2)$ is a factor of $f(x)$ .
Work Step by Step
The Remainder Theorem states that when a function $f(x)$ is divided by $(x-R)$ , then the remainder will be: $f(R)$.
Now, $f(2)=(4)(2)^4-(15)(2)^2-4=(4)(16)-(15)(4)-4=0$
The Factor Theorem states that if $f(a)=0$, then $(x-a)$ is a factor of $f(x)$ and vice versa.
Therefore, by the Factor Theorem $(x-2)$ is a factor of $f(x)$ .