Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.3 One-sided Limits; Continuous Functions - 13.3 Assess Your Understanding - Page 909: 43

$\dfrac{3}{2}$

We find the right-hand limit as follows: $\lim\limits_{x \to -2^{+}} \dfrac{x^2+x-2}{x^2+2x} \\=\lim\limits_{x \to -2^{+}} \dfrac{(x+2) (x-1)}{x(x+2)} \\=\lim\limits_{x \to -2^{+}} \dfrac{x-1}{x} \\=\dfrac{-2-1}{-2} \\=\dfrac{3}{2}$