Answer
$4$
Work Step by Step
We find the right-hand limit as follows:
$\lim\limits_{x \to 2^{+}} f(x)=\lim\limits_{x \to 2^{+}} \dfrac{x^2-4}{x-2} \\=\lim\limits_{x \to 2^{+}} \dfrac{(x-2)(x+2)}{x-2}) \\=\lim\limits_{x \to 2^{+}}(x+2) \\=2+2 \\=4$