Answer
$48$
Work Step by Step
We need to plug in $k=1$ to $k=4$ into the given summation.
Therefore, $\sum_{k=1}^4 (4k+2)=(4(1)+2)+(4(2)+2)+(4(3)+2)+(4(4)+2) \\ =6+10+14+18\\ =48$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 859: 5
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