Answer
$3825$
Work Step by Step
We know that
$\sum_{k=1}^{n} k =\dfrac{n(n+1)}{2}$
We plug in $30$ for $n$ in the given summation formula.
Therefore, $\sum_{k=1}^{50} (3k) =(3) \times \dfrac{50(50+1)}{2}=3825$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Chapter Review - Review Exercises - Page 859: 13
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