Answer
$(\dfrac{1}{10})^{10}=10^{-10}$
Work Step by Step
The $n^{th}$ term of a geometric sequence is given by the formula: $a_n = a_1 \ r^{(n-1)}(1)$
where, $a_1 = \ First \ Term$ and $r=\dfrac{a_2}{a_1}= \ Common \ Ratio$
We have: $a_1=1 $ and $r=\dfrac{a_2}{a_1}=\dfrac{1/10}{1} =\dfrac{1}{10}$
Plug in $11$ for $n$ into equation (1) to obtain:
$a_{11} = (1) \times (\dfrac{1}{10})^{(11-1)}=(\dfrac{1}{10})^{10}=10^{-10}$
