Answer
$ 12(5x-1)(6x+1)^{1/3}(4x-3)^{1/2}$
Work Step by Step
$6(6x+1)^{1/3}(4x-3)^{3/2}+6(6x+1)^{4/3}(4x-3)^{1/2}=6(6x+1)^{1/3}(4x-3)^{1/2}(4x-3+6x+1)=6(6x+1)^{1/3}(4x-3)^{1/2}(10x-2)=12(5x-1)(6x+1)^{1/3}(4x-3)^{1/2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A62: 96
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