Answer
$ (3x+5)^{1/3}(2x+3)^{1/2}(17x+27)$
Work Step by Step
$4(3x+5)^{1/3}(2x+3)^{3/2}+3(3x+5)^{4/3}(2x+3)^{1/2}=(3x+5)^{1/3}(2x+3)^{1/2}(4(2x+3)+3(3x+5))=(3x+5)^{1/3}(2x+3)^{1/2}(17x+27)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A62: 95
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