Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A62: 93

Answer

$ (x^2+4)^{1/3}(11x^2+12)$

Work Step by Step

$3(x^2+4)^{4/3}+x\cdot4(x^2+4)^{1/3}\cdot2x=(x^2+4)^{1/3}(3x^2+12+8x^2)=(x^2+4)^{1/3}(11x^2+12)$
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