Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A62: 110

$ T=\sqrt{ 2} \pi\ sec= 4.44\ sec .$

The period $T$ of a pendulum is given by $$ T=2\pi\sqrt{\frac{l}{32}}=2\pi\sqrt{\frac{16}{32}}=\frac{2}{ \sqrt{ 2}} \pi\ sec\\ = \sqrt{ 2} \pi\ sec .$$ Thus, we have $$ T=\sqrt{ 2} \pi\ sec= 4.44\ sec .$$