Answer
amplitude $1$, period $ \frac{2\pi}{3}$, vertical translation $2$ up, and phase shift $\frac{\pi}{15}$ to the right.
Work Step by Step
Given $y=2-\ sin(3x-\frac{\pi}{5})=2-\ sin[3(x-\frac{\pi}{15})]$, we can find the following: amplitude $1$, period $p=\frac{2\pi}{3}$, vertical translation $2$ up, and phase shift $\frac{\pi}{15}$ to the right.
