Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.4 Translations of the Graphs of the Sine and Cosine Functions - 6.4 Exercises - Page 613: 28

Answer

$y=cos(x-\frac{\pi}{6})$

Work Step by Step

The graph appears to be the result of $y=cos(x)$ shifted $\frac{\pi}{2}-\frac{\pi}{3}=\frac{\pi}{6}$ units to the right, thus the function is $y=cos(x-\frac{\pi}{6})$ Note: if you use $y=sin(x)$, you will have $d\lt 0$
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