Answer
B. Amplitude=3, Period=$\pi$, Phase shift=2.
Work Step by Step
Comparing $y=3\sin(2x-4)$ to $y=A\sin(\omega x-\phi)$, note that $A=3$, $\omega=2$, and $\phi=4$.
Amplitude=$|A|=3$
Period $T=\frac{2\pi}{\omega}=\frac{2\pi}{2}=\pi$ and
Phase shift = $\frac{\phi}{\omega}=\frac{4}{2}=2$
So the correct match is option B.