Answer
C
Work Step by Step
Comparing $y=-4\sin(3x-2)$ to $y=A\sin(\omega x-\phi)$, note that $A=-4$, $\omega=3$, and $\phi=2$.
Amplitude=$|A|=4$
Period $T=\frac{2\pi}{\omega}=\frac{2\pi}{3}$ and
Phase shift = $\frac{\phi}{\omega}=\frac{2}{3}$
Option C is the correct match.