Answer
$8\pi\ m/sec$
Work Step by Step
Given $r=12\ m, \omega=\frac{2\pi}{3}\ rad/sec$, we have $v=r\omega=12\times\frac{2\pi}{3}=8\pi\ m/sec$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 97
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