Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 115

Answer

$168\pi\ m/min$

Work Step by Step

The flywheel moves $2\pi\times42=84\pi$ radians per minute, thus $\omega=\frac{84\pi}{1}=84\pi\ rad/min$ and the linear speed is $v=r\omega=2\times84\pi=168\pi\ m/min$
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