Answer
$\frac{\pi}{18}\ rad/sec$
Work Step by Step
Given $s=\frac{8\pi}{9}\ m, r=\frac{4}{3}\ m, t=12\ sec$, we have $\omega=\frac{s}{r t}=\frac{\frac{8\pi}{9}}{\frac{4}{3}\times12}=\frac{\pi}{18}\ rad/sec$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 590: 108
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