Answer
$\frac{216\pi}{5}\ yd$
Work Step by Step
Given $r=9\ yd, \omega=\frac{2\pi}{5}\ rad/sec, t=12\ sec$, we have $s=r\omega t=9\times\frac{2\pi}{5}\times12=\frac{216\pi}{5}\ yd$
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