Answer
$B= 31^\circ 30'$, $b\approx458$, $c\approx877$
Work Step by Step
1. Use the figure given in the exercise, angle $A=58^\circ30'=58.5^\circ$, we have angle $B=90^\circ-A=90^\circ-58.5^\circ=31.5^\circ=31^\circ 30'$
2. We have $tanA=\frac{a}{b}$, thus $b=\frac{a}{tanA}=\frac{748}{tan(58.5^\circ)}\approx458$
3. Since $sinA=\frac{a}{c}$, we have $c=\frac{a}{sinA}=\frac{748}{sin(58.5^\circ)}\approx877$
