Answer
See answers below.
Work Step by Step
1. $-135^\circ$ is in quadrant III with a reference angle $\theta=180^\circ-135^\circ=45^\circ$
2. We have $sin(-135^\circ)=-sin\theta=-sin45^\circ=-\frac{\sqrt 2}{2}$
3. We have $cos(-135^\circ)=-cos\theta=-cos45^\circ=-\frac{\sqrt 2}{2}$
4. We have $tan(-135^\circ)=tan\theta=tan45^\circ=1$
5. We have $cot(-135^\circ)=cot\theta=cot45^\circ=1$
6. We have $sec(-135^\circ)=-sec\theta=-\frac{1}{cos\theta}=-\sqrt 2$
7. We have $csc(-135^\circ)=-csc\theta=-\frac{1}{sin\theta}=-\sqrt 2$
