Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Test - Page 563: 21

Answer

$240^\circ, 300^\circ$

Work Step by Step

Given $csc\theta=-\frac{2\sqrt 3}{3}$ and $\theta\in[0,360^\circ)$, we have $sin\theta=\frac{1}{csc\theta}=-\frac{\sqrt 3}{2}$, and we can find $\theta=240^\circ, 300^\circ$
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