Answer
$w= 8, x=4, y= 4\sqrt 3 , z= 4\sqrt 2$
Work Step by Step
Use the given figure and dimensions in the exercise, we have:
1. In the right triangle with a $45^\circ$, we have $x=4$ and $z=\frac{4}{sin45^\circ}=4\sqrt 2$
2. In the right triangle with a $30^\circ$, we have $w=\frac{4}{sin30^\circ}=4\times2=8$ and $y=w\ cos30^\circ=4\sqrt 3$
