Answer
$82^{0}$
$\Rightarrow 57\rightarrow C$
Work Step by Step
$\theta =98^{0}\left( Q2\right) \Rightarrow \theta '=180^{0}-\theta =\left( 180-98\right) ^{0}=82^{0}$
$\Rightarrow 57\rightarrow C$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 57
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