Answer
$a=12;$
$b=12\sqrt {3}$
$c=12\sqrt {6};$
$d=c=12\sqrt {6}$
Work Step by Step
$a=24\times \cos 60^{0}=24\times \dfrac {1}{2}=12;$
$b=24\times \sin 60^{0}=12\sqrt {3}$
$c=\dfrac {b}{\cos 45}=\dfrac {12\sqrt {3}}{\dfrac {\sqrt {2}}{2}}=12\sqrt {6};$
$d=c=12\sqrt {6}$