Answer
$r=15\sqrt {2};$
$p=15$
$t=10\sqrt {6}$
$q=5\sqrt {6}$
Work Step by Step
$r=\dfrac {15}{\cos 45}=15\sqrt {2};$
$p=r\sin 45=15$
$t=\dfrac {r}{\cos 30}=\dfrac {15\sqrt {2}}{\dfrac {\sqrt {3}}{2}}=10\sqrt {6}$
$q=r\tan 30^{0}=\dfrac {15\sqrt {2}}{\sqrt {3}}=5\sqrt {6}$
