Answer
$\dfrac {1}{2}$
Work Step by Step
$\cos 60^{0}=\sqrt {1-\sin ^{2}60}=\sqrt {1-\left( \dfrac {\sqrt {3}}{2}\right) ^{2}}=\dfrac {1}{2}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 532: 44
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