Answer
$(5x-2)(3x+1)$
Work Step by Step
Factoring $ ax^{2}+bx+c $, we search for factors of $ ac $ whose sum is $ b.$
If they exist, we rewrite $ bx $ and factor in pairs.
We see that $-6$ and $5$ are factors of $15(-2)=-30$, and their sum is $-1.$
$15x^{2}-x-2=15x^{2}-6x+5x-2$
$=3x(5x-2)+(5x-2)$
$=(5x-2)(3x+1)$
