Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 64

Answer

$\frac{1}{5}$

Work Step by Step

Recall that $a^{x/y}=\sqrt[y] {a^x}$. Also recall that the negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. Use these rules to simplify: $25^{-1/2}=\frac{1}{25^{1/2}}=\frac{1}{\sqrt{25}}=\frac{1}{5}$
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